QUESTION 19
When configuring a serial interface on a router, what is the default encapsulation? A. atm-dxi B. frame-relay C. hdlc D. lapb E. ppp |
問題19
當在路由器上配置一個串列接口, 何者是預設的封裝? A. atm-dxi B. frame-relay C. hdlc D. lapb E. ppp |
答:C
缺省封裝是HDLC |
QUESTION 26
Which three options are valid WAN connectivity methods? (Choose three.) A. PPP B. WAP C. HDLC D. MPLS E. L2TPv3 F. ATM. |
問題26
哪三個選項是有效的廣域網連接方式?(選擇三項) A. PPP B. WAP C. HDLC D. MPLS E. L2TPv3 F. ATM. |
答:ACF
哪三種封裝屬於WAN鏈路的? A:點到點協議,正確 B:無線加密技術,錯誤 C:思科缺省封裝格式,正確。 D:多協議標籤轉換,錯誤 E:隧道協議,錯誤 F:正確。 |
QUESTION 27
Refer to the exhibit. Which WAN protocol is being used? A. ATM B. HDLC C. Frame Relay D. PPP. |
問題27
圖示中使用哪個WAN協議? A. ATM B. HDLC C. Frame Relay D. PPP |
答:C
由圖中的紅線可看到發送接受LMI信息。屬於FR的數據包。 |
QUESTION 28
What is the difference between a CSU/DSU and a modem? A. A CSU/DSU converts analog signals from a router to a leased line; a modem converts analog signals from a router to a leased line. B. A CSU/DSU converts analog signals from a router to a phone line; a modem converts digital signals from a router to a leased line. C. A CSU/DSU converts digital signals from a router to a phone line; a modem converts analog signals from a router to a phone line. D. A CSU/DSU converts digital signals from a router to a leased line; a modem converts digital signals from a router to a phone line. |
問題28
CSU / DSU和數據機之間的區別是什麼? A. 一個CSU / DSU將模擬信號轉換,從一個路由器到租用線路,調製解調器將模擬信號轉換,從一個路由器到租用線路。 B. 一個CSU / DSU將模擬信號轉換,從一個路由器到電話線,調製解調器將數字信號轉換,從一個路由器到租用線路。 C. 一個CSU / DSU將數字信號轉換,從一個路由器到電話線,調製解調器將模擬信號轉換,從一個路由器到電話線。 D. 一個CSU / DSU將數字信號轉換,從一個路由器到租用線路,調製解調器將數字信號轉換,從一個路由器到電話線。 |
答:D
CSU/DSU一般是專線,MODEN是將模擬信號與數字信號轉換 |
QUESTION 30
When troubleshooting a Frame Relay connection, what is the first step when performing a loopback test? A. Set the encapsulation of the interface to HDLC. B. Place the CSU/DSU in local-loop mode. C. Enable local-loop mode on the DCE Frame Relay router. D. Verify that the encapsulation is set to Frame Relay. |
問題30
當進行幀中繼連結的排除故障時,什麼是進行環回測試的第一步驟? A. 設置接口HDLC協議的封裝。 B.將CSU / DSU在本地循環模式。 C. DCE幀中繼路由器上啟用本地環路模式。 D.驗證的封裝幀中繼。 |
答:A
在對FR進行排錯的時候,當做回環測試的時候,第一步如何處理? A:講接口配置成HDLC,正確,FR封裝下無法正常ping自己端口 |
QUESTION 31
What occurs on a Frame Relay network when the CIR is exceeded? A. All TCP traffic is marked discard eligible. B. All UDP traffic is marked discard eligible and a BECN is sent. C. All TCP traffic is marked discard eligible and a BECN is sent. D. All traffic exceeding the CIR is marked discard eligible. |
問題31
當CIR超過的時候, 幀中繼網絡時會發生什麼事? A. 所有TCP流量被標記為可丟棄的。 B. 所有的UDP流量標記為可丟棄,並一個BECN發送。 C.所有TCP流量被標記為可丟棄,並一個BECN發送。 D.所有流量超過CIR標記為可丟棄的。 |
答:D
在FR網絡中,當CIR超過時會發生什麼情況?D:所有超過的流量都丟棄。 |
QUESTION 32
What are two characteristics of Frame Relay point-to-point subinterfaces? (Choose two.) A. They create split-horizon issues. B. They require a unique subnet within a routing domain. C. They emulate leased lines. D. They are ideal for full-mesh topologies. E. They require the use of NBMA options when using OSPF.. |
問題32
幀中繼點至點的子接口的兩個特點是什麼?(選擇兩項) A. 他們創造了水平分割的問題。 B. 他們需要一個獨立的子網內的路由域。 C.他們模擬租用線路。 D. 他們是理想的全網狀拓撲結構。 E. 他們需要使用OSPF的NBMA選項時使用。 |
答:BC
幀中繼點到點子接口的特點? A:水平分割,錯誤。 B:每個子接口需要一個獨立的網段,正確。 C:類似專線,正確。 D:全網互聯是理想拓撲,錯誤。通常是hub-spoke E:NBMA不支持OSPF,錯誤。 |
QUESTION 33
Refer to the exhibit. Addresses within the range 10.10.10.0/24 are not being translated to the 1.1.128.0/16 range. Which command shows if 10.10.10.0/24 are allowed inside addresses? A. debug ip nat B. show access -list C. show ip nat translation D. show ip nat statistics |
問題33
請參閱圖示。網址範圍10.10.10.0/24內尚未轉換至範圍1.128.0/16。如果10.10.10.0/24能夠允許於內部地址, 哪個指令可以顯示? A. debug ip nat B. show access -list C. show ip nat translation D. show ip nat statistics |
答:B
那條命令可以看到10.10.10.0/24是否在允許轉換範圍 。允許的範圍是通過ACL定義的。 A:打開NAT轉換的debug信息,錯誤 B:查看acl信息,正確。 C:查看NAT轉換錶,錯誤。 D:查看靜態NAT。錯誤 |
QUESTION 52
Refer to the exhibit. Which command would allow the translations to be created on the router? A. ip nat pool mynats 1.1.128.1 1.1.135.254 prefix-length 19 B. ip nat outside mynats 1.1.128.1 1.1.135.254 prefix-length 19 C. ip nat pool mynats 1.1.128.1 1.1.135.254 prefix-length 18 D. ip nat outside mynats 1.1.128.1 1.1.135.254 prefix-length 18 |
問題52
請參閱圖示。哪個指令將允許建立在路由器上的轉換? A. ip nat pool mynats 1.1.128.1 1.1.135.254 prefix-length 19 B. ip nat outside mynats 1.1.128.1 1.1.135.254 prefix-length 19 C. ip nat pool mynats 1.1.128.1 1.1.135.254 prefix-length 18 D. ip nat outside mynats 1.1.128.1 1.1.135.254 prefix-length 18 |
答:A
prefix-length 表示掩碼的長度。prefix-length 19表示掩碼為255.255.224.0 135-128=7,7=3bits所以正確為32-8-3=21,選最接近的19 |
QUESTION 56
Refer to the exhibit. W hat does the (*) represent in the output? A. Packet is destined for a local interface to the router. B. Packet was translated, but no response was received from the distant device. C. Packet was not translated, because no additional ports are available. D. Packet was translated and fast switched to the destination. |
問題56
請參閱圖示。(*)在輸出代表的是什麼意思? A. 數據包被發往本地接口的路由器。 B. 數據包轉換,但沒有收到響應,從遙遠的設備。 C.數據包沒有翻譯,因為沒有額外的端口是可用的。 D. 數據包翻譯和快速切換的目的。 |
答:D
由圖中提示信息可以看出,源為10.10.0.2已經有個一個轉換,所以後續的數據包快速轉發。 |